Radical denesting or Dynesty???

Algebra Level 5

Evaluate

3 15 8 + 3 2 + 3 8 + 3 8 2 × 2 . ^3 \sqrt{\dfrac{15}{8}+\sqrt{\dfrac{3}{2}+\sqrt{\dfrac{3}{8}+\sqrt{\dfrac{3}{8^2 \times 2}\cdots}}}}.


The answer is 1.5.

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1 solution

3 2 + 3 8 + 3 8 2 × 2 t o \color{#3D99F6}{\sqrt{\frac{3}{2}+\sqrt{\frac{3}{8}+\sqrt{\frac{3}{8^2\times2}\dotsm\;to\;\infty}}}} Can be written as 1 2 6 + 6 + 6 + \color{#D61F06}{\frac{1}{2}\sqrt{6+\sqrt{6+\sqrt{6+\dotsm}}}} .Let 6 + 6 + = x \color{#69047E}{\sqrt{6+\sqrt{6+\dotsm}}=x} .Then it can be written as: 6 + x = x 6 + x = x 2 x 2 x 6 = 0 x 2 + 2 x 3 x 6 = 0 x ( x + 2 ) 3 ( x + 2 ) = 0 ( x 3 ) ( x + 2 ) = 0 x = 3 o r x = 2 \color{#20A900}{\sqrt{6+x}=x\\6+x=x^2\\x^2-x-6=0\\x^2+2x-3x-6=0\rightarrow x(x+2)-3(x+2)=0\rightarrow(x-3)(x+2)=0\rightarrow x=3\;or\;x=-2} As the nested radical is positive so discard the negative root.The radical in the question can be written as: 15 8 + 1 2 6 + 6 + 3 = 15 8 + 1 2 × 3 3 = 15 8 + 3 2 3 = 15 + 12 8 3 = 27 8 3 = 3 2 = 1.5 \color{#3D99F6}{\sqrt[3]{\frac{15}{8}+\frac{1}{2}\sqrt{6+\sqrt{6+\dotsm}}}\\=\sqrt[3]{\frac{15}{8}+\frac{1}{2}\times3}\\=\sqrt[3]{\frac{15}{8}+\frac{3}{2}}\\=\sqrt[3]{\frac{15+12}{8}}\\=\sqrt[3]{\frac{27}{8}}=\frac{3}{2}=\boxed{1.5}}

How 3 2 + 3 8 + 3 8 2 × 2 t o \color{#3D99F6}{\sqrt{\frac{3}{2}+\sqrt{\frac{3}{8}+\sqrt{\frac{3}{8^2\times2}\dotsm\;to\;\infty}}}} can be written as 1 2 6 + 6 + 6 + \color{#D61F06}{\frac{1}{2}\sqrt{6+\sqrt{6+\sqrt{6+\dotsm}}}} ?

Anandhu Raj - 6 years, 4 months ago

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