Evaluate
3 8 1 5 + 2 3 + 8 3 + 8 2 × 2 3 ⋯ .
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How 2 3 + 8 3 + 8 2 × 2 3 ⋯ t o ∞ can be written as 2 1 6 + 6 + 6 + ⋯ ?
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2 3 + 8 3 + 8 2 × 2 3 ⋯ t o ∞ Can be written as 2 1 6 + 6 + 6 + ⋯ .Let 6 + 6 + ⋯ = x .Then it can be written as: 6 + x = x 6 + x = x 2 x 2 − x − 6 = 0 x 2 + 2 x − 3 x − 6 = 0 → x ( x + 2 ) − 3 ( x + 2 ) = 0 → ( x − 3 ) ( x + 2 ) = 0 → x = 3 o r x = − 2 As the nested radical is positive so discard the negative root.The radical in the question can be written as: 3 8 1 5 + 2 1 6 + 6 + ⋯ = 3 8 1 5 + 2 1 × 3 = 3 8 1 5 + 2 3 = 3 8 1 5 + 1 2 = 3 8 2 7 = 2 3 = 1 . 5