Radical Equation for X

Using $(a+b)^3=a^3+b^3+3ab(a+b)$ where $a=\sqrt[3]{9+\sqrt{x}}$ and $b=\sqrt[3]{9-\sqrt{x}}$ , $\sqrt[3]{9+\sqrt{x}}+\sqrt[3]{9-\sqrt{x}}=3\sqrt[3]{2}$ $\Rightarrow 18+3(3\sqrt[3]{2})\sqrt[3]{81-x}=54$ $\Rightarrow \sqrt[3]{81-x}=2\sqrt[3]{4}$ $\Rightarrow 81-x=32$ $\Rightarrow x=\boxed{49}$