Radical Pie

$\sqrt{x^2}=|x|$

$|3-3.14|+|3.14-3|=0.14+0.14=0.28$

$\sqrt{(3-3.14)^2}+\sqrt{(3.14-3)}$ $=\sqrt{(-0.14)^2}+\sqrt{(0.14)^2}$ $=\sqrt{(0.14)^2}+\sqrt{(0.14)^2}$ $=0.14+0.14$ $=\boxed{0.28}$

since $3 \leq3.14$ then $3-3.14\leq0$ thus $3.14-3\geq0$ Now we have $\sqrt{ ( 3 - 3.14) ^2 } + \sqrt{ ( 3.14 - 3 ) ^ 2 }.$ and we know that $\sqrt{x^2}=|x|$ thus $|3-3.14|+|3.14-3|=-(3-3.14)+(3.14-3)=3.14-3+3.14-3$ $=0.28$

(3.14 - 3)^2 = (3 - 3.14)^2 = (0.14)^2

So

square root of [(3 - 3.14)^2] + square root of [( 3.14 - 3)^2] = (0.14) + (0.14) = 0.28

(3 - 3.14) + 3.14 - 3) = -.14 + .14 So root of (3 - 3.14)^2 + root of (3.14 - 3)^2 = root of (-.14)^2 + root of(.14)^2 = .14+.14 = .28

± (3-3.14) ± (3.14-3)

If we consider both signs as '+' or '-', then we get zero.

If we consider opposite signs then we get 0.28 as the solution.

Both solutions are possible but one matching with the option is considered.

Just to support ±;

√16 = +4 and -4, or we can say ±4

The first part of the sum = 0.14 = The second part of the sum.

Thus the answer is 0.14 + 0.14 = 0.28