Radius please

Geometry Level 2

The smaller circle touches the bigger circle and also its perpendicular diameters. If the radius of the smaller circle is 2 cm, find the radius of the bigger circle.


The answer is 4.828.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Nishant Ranjan
Nov 18, 2019

Let us focus on only the quadrant containing the smaller circle.

Notice that we can make a right angled triangle O'AO with side lengths:

O'A = 2cm (radius of small circle)

AO = 2cm (obviously)

Now, use Pythagoras theorem:

h 2 = p 2 + b 2 h^{2} = p^{2} + b^{2} = > O O 2 = O A 2 + A O 2 => O'O^{2} = O'A^{2} + AO^{2} = > O O 2 = 4 + 4 =>O'O^2 = 4 + 4 = > O O = 2 2 =>O'O = 2\sqrt{2}

Now, the required length is OP.

O P = O O + O P OP = O'O + O'P O P = r a d i u s = 2 c m O'P = radius = 2cm T h u s , Thus, O P = 2 2 + 2 = 4.828 ( A p p r o x i m a t e l y ) OP = 2\sqrt{2} + 2 = \boxed{~ 4.828} (Approximately)

I just barely got it right on my last attempt. I recently learned inversive geometry and was experimenting with this sort of circle packing thing, was going to be really mad if I didnt get it right to get opportunity to post solution to let people know that i know this kind of stuff

chase marangu - 1 year, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...