Ramanujan got convoluted

Let μ \mu and ϕ \phi be two number theoretic functions. Then

evaluate ( μ ϕ ) ( 1729 ) (\mu * \phi) (1729)


Notations :-

ϕ \phi denotes Euler's Totient function.

μ \mu denotes Möbius function.

* denotes Dirichlet's convolution of two arithmetic functions.


The answer is 935.

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1 solution

Otto Bretscher
Apr 10, 2016

For a prime p p we have ( μ ϕ ) ( p ) = μ ( p ) ϕ ( 1 ) + μ ( 1 ) ϕ ( p ) = p 2 (\mu*\phi)(p)=\mu(p)\phi(1)+\mu(1)\phi(p)=p-2 . Since the function is multiplicative, we find ( μ ϕ ) ( 1729 ) = ( μ ϕ ) ( 7 ) × ( μ ϕ ) ( 13 ) × ( μ ϕ ) ( 19 ) = 5 × 11 × 17 = 935 (\mu*\phi)(1729)=(\mu*\phi)(7)\times(\mu*\phi)(13)\times (\mu*\phi)(19)=5\times 11\times 17=\boxed{935}

Yes this is the shortest wayto deal with this problem :) :) I did it by converting the convolution to standard form and then with divisors...that was long way....nice solution upvoted..:) :)

A Former Brilliant Member - 5 years, 2 months ago

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