Random Sleep Times

Ephram sleeps at a random time between 10PM and 11PM and he sleeps at a random time between 8 and 10 hours. The probability that he wakes up before his 1st class at 8:30 can be expressed as m n \frac{m}{n} . Find m + n m+n .


The answer is 31.

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1 solution

Eric Roberts
Jan 27, 2021

If Ephram goes to sleep at 10pm he can wake between 6 am and 8 am. Likewise, If he goes to sleep at 11 pm he may wake between 7 am and 9 am. Any other sleep/awake state is enclosed in the parallelogram formed by the vertices ( 6, 10 ),( 8, 10 ),( 7, 11 ),( 9, 11 ) as shown in the graph below:

The probability of Ephram waking after 8:30 is the area of the purple triangle divided by the total area of the parallelogram.

P ( W > 8 : 30 ) = 1 2 0.5 0.5 2 1 = ( 1 2 ) 4 \begin{aligned} P ( W > 8:30 ) &= \frac{ \frac{1}{2} \cdot 0.5 \cdot 0.5 }{ 2 \cdot 1} \\ &= \left( \frac{1}{2} \right)^4 \end{aligned}

Thus the probability of him waking before 8:30:

P ( W < 8 : 30 ) = 1 P ( W > 8 : 30 ) = 1 ( 1 2 ) 4 = 15 16 \begin{aligned} P( W < 8:30 ) &= 1 - P ( W > 8:30 ) \\ &= 1 - \left( \frac{1}{2} \right)^4 \\ &= \frac{15}{16} \end{aligned}

Thus;

m + n = 31 m+n = 31

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