Paul has once again drunk too much and been driven home by taxi. At home, he still has steps to his doorstep. Since Paul is completely drunk, he makes a step forward (to home) with probability and a step back with probability If he gets back into the taxi (which is only one step away from cell 0 in the diagram), the taxi driver drives him directly to the next police station, so he can spend the night in the sobering-up cell.
What is the probability of Paul reaching his front door (in percent) to 3 decimal places?
Bonus problem: Solve the problem for arbitrary and .
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All possible outcomes can be represented by a tree diagram The numbers indicates the probabilitiy of Paul reaching the corresponding state. Paul gets to his front door on the first try with a probability p 1 = 4 1 , on the second try with p 2 = 1 6 1 , and so on. For the m th try, the probability reads p m ⇒ P = 4 m 1 = m = 1 ∑ ∞ p m = 4 1 m = 0 ∑ ∞ 4 m 1 = 4 1 1 − 1 / 4 1 = 3 1 with the help of the geometric series ∑ m = 0 ∞ r m = 1 − r 1 .