Ranger

As $x$ Approaches infinity the value of y approaches 0. And when x approaches 0 y approaches infinity someone may remind me tomorrow to upload an image as I am shuting down

We will get that $\displaystyle\lim_{x\rightarrow\infty}\frac{1}{x^2} = 0$ and $\displaystyle\lim_{x\rightarrow0}\frac{1}{x^2} = \infty$ , but the value is never zero, therefore $\displaystyle y\in(0, \infty)$