Rate of Diffusion.

Chemistry Level 1

A gas $G_1$ has a molar mass of 144 g/mol and a diffusion rate of $D_1.$ Another gas $G_2$ has a molar mass of 36 g/mol and a diffusion rate of $D_2.$ Find the value of $\frac{D1}{D2} +1.$

1.25 1.5 3 5

1 solution

Vishwas H K
May 19, 2014

Basic law of Rate of Diffusion inversely proportional to root of its molar mass.

$D \alpha 1/ \sqrt { M }$

$D_{1}/D_{2} = \sqrt { M_{ 2 } } /\sqrt { M_{ 1 } }$

$D_{1}/D_{2}=\sqrt { 36 } /\sqrt { 144}$

$D_{1}/D_{2}=6/12$

$D_{1}/D_{2} + 1=(1/2)+1 = 1.5$

Yeah it's as easy as that!

Umang Vasani - 7 years ago

@Vishwas H K its not diffusion its effusion,there is a difference (though slight) b/w the 2. Given by Graham 's Law.

Ayon Ghosh - 4 years, 2 months ago

Isnt its name Graham's Law of Diffusion

Md Zuhair - 4 years, 1 month ago

Rate of Diffusion.

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