Ratio and Proportion Word Problems: Treadmill

Algebra Level 2

Calvin can run on a treadmill at a steady 6 6 miles per hour pace. How long (in minutes) will it take for him to run 13 miles?


The answer is 130.

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3 solutions

Brilliant Mathematics Staff
Aug 1, 2020

Time = Distance Speed = \frac{ \mbox{Distance} } { \mbox{Speed} } .

Solution 1: Since he runs 6 miles per hour, it will take him 13 6 \frac { 13 } {6} hours, or equivalently 13 6 × 60 = 130 \frac {13 } { 6} \times 60 = 130 minutes.

Solution 2: Since he runs 6 miles per hour, it will take him 60 6 = 10 \frac {60}{6} = 10 minutes to run 1 mile. Hence, it will take him 10 × 13 = 130 10 \times 13 = 130 minutes to run 13 miles.

Hey @Brilliant Mathematics , I have to ask my query here since you've closed the 'Notify staff' discussion. There's something wrong with my Contributions page. In my solutions, it doesn't show up in the order of up-votes. A solution with 3 up-votes is higher than one with 66. Here's a pic -

Please help :)

A Former Brilliant Member - 6 months, 3 weeks ago

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Hi Percy, we do not sort the solutions by the number of upvotes they received.

Brilliant Mathematics Staff - 6 months, 3 weeks ago

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Oh...it was that way in everybody's profile, so I though there's something wrong with mine. Also, the big-bolded text says ' Top Solutions '...

A Former Brilliant Member - 6 months, 3 weeks ago
Aaron Ma
Feb 20, 2021

Because Calvin can run on a treadmill at 6 6 miles per hour, Calvin runs 60 ÷ 6 = 10 60 \div 6 = 10 miles per minute. To run 13 13 miles, Calvin needs 10 13 = 130 10 * 13 = 130 minutes.

Mahdi Raza
Aug 20, 2020

6 miles 60 minutes 1 mile 10 minutes 13 miles 130 minutes \dfrac{6 \text{ miles}}{60 \text{ minutes}} \implies \dfrac{1 \text{ mile}}{10 \text{ minutes}} \implies \dfrac{13 \text{ miles}}{\boxed{130} \text{ minutes}}

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