ratio of the green area to the red area

Geometry Level 2

All arcs shown in the figure above are equal semi-circles. What is the ratio of the green area to the red area?

3 π 2 3 3 π \dfrac{3\pi}{2\sqrt{3}-3\pi} 4 3 π 3 π \dfrac{4\sqrt{3}-\pi}{3\pi} 3 π 8 \dfrac{3\pi}{8} π 4 3 π \dfrac{\pi}{4\sqrt{3}-\pi}

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1 solution

Rab Gani
Feb 16, 2019

Let the diameter of the semicircle is d. The regular hexagon area is the sum of red area and the green area, A = 3(d^2 sin 60) = 1.5√3 d^2 .The green area = (3/8)π d^2 . The ratio of the green area to the red area = [(3/8)π d^2]/ [1.5√3 d^2 - (3/8)π d^2 ] = π/[4√3 – π]

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