Ratio problem 1 by Dhaval Furia

Algebra Level pending

In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali . After a review, the score of each of them increased by 6 . The revised scores of Anjali , Mohan , and Rama were in the ratio 11 : 10 : 3 11:10:3 . Then Anjali's score exceeded Rama's score by _____

26 26 24 24 35 35 32 32

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1 solution

Let the scores obtained by Rama, Mohan and Anjali initially be R , M R, M and A A respectively. Then M + A = 12 R M+A=12R . Let finally A + 6 = 11 x , M + 6 = 10 x , R + 6 = 3 x A+6=11x, M+6=10x, R+6=3x . Then

11 x 6 + 10 x 6 = 12 ( 3 x 6 ) x = 60 15 = 4 11x-6+10x-6=12(3x-6)\implies x=\dfrac{60}{15}=4 , and R = 3 × 4 6 = 6 , M = 10 × 4 6 = 34 , A = 11 × 4 6 = 38 R=3\times 4-6=6, M=10\times 4-6=34, A=11\times 4-6=38 .

Therefore A R = 38 6 = 32 A-R=38-6=\boxed {32} years.

32 "years" ???

Dhaval Furia - 1 year ago

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