Ratio problem
A beggar had 10 paisa , 20 paisa and 1 rupee coins in the ratio of 10 :17 : 7 respectively at the end of day. If that day he earned a total of Rs. 57 , how many 20 paisa coins did he have?
The answer is 85.
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1 solution
57.00 = (10n)(0.10) + (17n)(0.20) + (7n)(1.00)
= n + 3.4n + 7n
= 11.4n
n = 57.00 / 11.40 = 5
Answer = 17n = 85