Rationally irrational?

Given that a a is rational , and b b is irrational , can a b ab be rational?

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1 solution

Geoff Pilling
Aug 2, 2016

If a = 0 a = 0 and b = 2 , b =\sqrt{2}, , then a b = 0 ab = 0 , which is rational. So the answer is Yes \boxed{\mbox{Yes}}

Bonus: Prove that this is only possible when a = 0. a=0.

Eli Ross Staff - 4 years, 10 months ago

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Assume a 0 a \neq 0 . Let a b = r ab=r where r r is rational:

a b = r b = r a ab=r \implies b=\dfrac{r}{a}

But r a \dfrac{r}{a} is rational as a 0 a \neq 0 but this contradicts b b being irrational so a = 0 a=0 .

Sam Bealing - 4 years, 10 months ago

Suppose that a is rational and not equal 0; then a = e/f for integers e,f with e not = 0. If ab is rational, b irrational, then ab = k/m, and b = (k/m)*((f/e) = kf/me, a contradiction.

Edwin Gray - 2 years, 3 months ago

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