A 5 capacitor is connected in series to a 4 battery, a 3 resistor, and a switch. What is the charge on the capacitor, in , when the switch has been closed for ?
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Relevant wiki: RC Circuits (Direct Current)
The equation for the charge on the capacitor in and RC circuit is
q = q m a x ( 1 − e τ − t ) .
Given t = 1 5 ln 1 0 s , calculate
q m a x = ε C = ( 4 V ) ( 5 F ) = 2 0 C
and
τ = R C = ( 3 Ω ) ( 5 F ) = 1 5 s .
Hence,
q = q m a x ( 1 − e τ − t ) = 2 0 ( 1 − e 1 5 − 1 5 ln 1 0 ) = 2 0 ( 1 − e − ln 1 0 ) = 2 0 ( 1 − 0 . 1 ) = 1 8 C .