Dan and Sam play a game in which the first to start says the number 1, the next says 2, and the one who's next must say an integer number between the number previously said and its cube (but not including).
For example, Dan begins saying 1, then Sam says 2, and then Dan can say whichever number he wants between 2 and 8; that is, he can reply 3, 4, 5, 6 or 7.
The game finishes when someone reaches 216000000 (who is the winner ). If Dan begins, who will win? This means, who has a winning strategy?
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I would not say whoever say 512 will win, just that who force the opponent to say 9-511 will win
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Tran Hieu, nice thinking and analysis. I understand what you are trying to say here, as I myself thought the same thing, but to present the solution in a more simpler way, I thought to write as I wrote. Thanks a lot! :), for bringing this point
A person who can choose x can ensure that he can get x 3 to x 3 + 3 x 2 + 3 x irrespective of the choice of the other player.
Thus if a person needs to choose any number, he must make sure to choose its cuberoot rounded down!
3 2 1 6 0 0 0 0 0 0 = 6 0 0 , 3 6 0 0 = 8 . 4 , 3 8 = 2
So who chooses 2 will choose 2160000000
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