Reading a graph

  • The velocity vs time graphic below describes how velocity of an object changes as a function of time, starting at point P ( t P = 0 t_{P}=0 ):
  • A: v P 0 v_{P}\neq 0
  • B: Between points P and Q, the object DECELERATES
  • C: v Q = 0 v_{Q}= 0
  • D: after point Q, the object ACCELERATES

Which statement is FALSE? (There might be more than one WRONG statement).

B None of them C D All of them A B and D A and C

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1 solution

P0156 M
Feb 20, 2018

Speeding up means that the magnitude (or numerical value) of the velocity is getting large (E.g. 1 m/s to 2 m/s is speeding up, -1 m/s to -2 m/s is also speeding up). In each case, the magnitude of the velocity (the number itself, not the sign or direction) is increasing; the speed is getting bigger. So, in this case, the object is decelerating between points P and Q. It is also true that vQ=0 and vP is greater than 0, and that after point Q the object accelerates, since the velocity, in magnitude, increases. None of the statements are wrong.

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