Ready for liftoff

From Newton's second law, we know that F = ma. Here, we are told the total mass of the rocket, payload, and fuel. Multiplying this value by the acceleration of gravity gives the total force (in Newtons) created by this combination of rocket mass and acceleration. This tells us the force created is -19,600,000 N, directed downward towards Earth. Therefore, the rocket needs to create a thrust that has a magnitude equal to or greater than this force, but with an opposite direction (therefore removing the negative sign) to start moving from its launch platform

based on Newton's second law , F=ma , the mass of rocket,etc. is $2 \times 10^6$ kg and g = 9.8 m/s , so the force created by the rocket is

F = - ( $2 \times 10^6 \times 9.8$ )

F = - ( $19.6 \times 10^6$ ) the negative (-) sign tells us the force is directed downward to the center of the earth. therefore, the rocket needs to create a thrust that is equal or greater than this force ( - ( $19.6 \times 10^6$ ) ) , but in opposite direction, that explains there's no negative sign so the rocket can fly from its platform

thus, the answer is = $19.6 \times 10^6$ or written as 19.6E6

*sorry for bad grammar :-)

The rocket will just start going up as soon as the normal force applied by it on ground becomes zero. The normal reduces according to upthrust force by fuel.So, total upthrust required equals to to the total normal applied by the rocket on the ground=mg=(2 10^6) (9.8)=1.96*10^7 N

F=ma....

F = 2E6 * 9.8 = 19.6E6