Real addition#1

Logic Level 3

In the following addition, different letters represent different digits, S E V E N , S I X , T W E N T Y \overline { SEVEN } ,\overline { SIX } ,\overline { TWENTY } are 5-digit, 3-digit and 6-digit numbers respectively

What is the value of S E V E N + S I X \overline { SEVEN } +\overline { SIX } ?


The answer is 69432.

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1 solution

All the digits of a number lie between 0 0 and 9 9 inclusive. So the valid equations are (since all the letters represent distinct digits) :

(i) 2 E + 2 = 10 + E 2E+2=10+E , or E = 8 E=8

(ii) 2 E + I = 20 + T 2E+I=20+T , so that T = 1 , I = 5 T=1, I=5

(iii) 2 S + 1 = 10 + W 2S+1=10+W , so that W = 3 , S = 6 W=3, S=6

(iv) 2 V + 8 = 20 + N 2V+8=20+N , so that V = 7 , N = 2 V=7, N=2

(v) 2 N + X = Y 2N+X=Y , so that X = 0 , Y = 4 X=0, Y=4

Hence S E V E N = 68782 , S I X = 650 \overline {SEVEN}=68782, \overline {SIX}=650 , and the final answer is 69432 \boxed {69432}

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