Real + Complex

Algebra Level 4

IF

( i x − k y ) 2 + ( i y − k z ) 2 + ( i z − k x ) 2 = ( i y − k x ) 2 + ( i x − k z ) 2 + ( i z − k y ) 2 ( ix - ky)^{2} + ( iy - kz)^{2} + ( iz - kx)^{2} = (iy - kx)^{2} +( ix - kz)^{2} +( iz - ky)^{2}

( i x − k y ) 4 + ( i y − k z ) 4 + ( i z − k x ) 4 = ( i y − k x ) 4 + ( i x − k z ) 4 + ( i z − k y ) 4 ( ix - ky)^{4} + ( iy - kz)^{4} + ( iz - kx)^{4} = (iy - kx)^{4} +( ix - kz)^{4} +( iz - ky)^{4}

then x + y + z = x + y + z =


The answer is 0.

U Z by U Z , 24, Guyana

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1 solution

By putting x=y=z=0 , all equations are satisfied

1 Helpful 0 Interesting 0 Brilliant 0 Confused

I did the same.

Prakhar Gupta - 6 years, 4 months ago

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