Real numbers

Greatest 6 didgit number is 999999.Now the required number must be a divisible by the LCM of 24,15 and 36

which is LCM(24 , 15 , 36) = ${ 2 }^{ 3 }\times { 3 }^{ 2 }\times { 5 }^{ 1 }$ = $360$

Hence the required number will be

$= 999999-999999\div \quad 360$

$=999999-279$

$=999720$

Just take a calculator divide the greatest 6 digit no. i.e. 999999 by 360 (L.C.M. of 24,15, 36) , you will surely get a number 2777.775, so take the number excluding the decimal digits, which is 2777.

now, multiply 2777 with 360=999720

Take the L.C.M of 24,15,36 i.e.360. Divide greatest 6-digit number i.e. 999999 by 360 and remainder will be 279. Then, subtract 279 from 999999 and you will get the answer i.e.999720

take LCM of 36,15,24=360 divide 999999 by 360 remainder is 279 subtract 279 from 999999=999720 ans.