real ones2

For what real number/s x x is the equation ( x 2 + 6 x + 10 ) x 2 + 2 (x^2 + 6x + 10)^{x^2+2} = 1 true?


The answer is -3.

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1 solution

Montesa Joy Rebao
Nov 13, 2014

case I: a^b=1 when b=0

x^2 + 2=0 will not yield real number solutions

case II: a^b=1 when a=1

x^2 + 6x + 10 = 1

x= -3

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