Real solution lost?

Algebra Level pending

How many real solution does the equation x 7 + 14 x 5 + 16 x 3 + 30 x 560 = 0 x^7 + 14x^5 + 16x^3 + 30x - 560 = 0 have?

7 3 2 6 5 1 4 Infinitely many

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1 solution

Deepak Kumar
Aug 9, 2016

An odd degree polynomial function must have at least one real root.Now taking derivative of the polynomial function on LHS,we see all powers are even and all coefficients are also positive indicating f'(x)>0 always.Hence f(x) is monotonically increasing giving number of real roots equal to 1

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