Reallocate Seats

5 students are arranged in a line.

If a teacher randomly reallocates their seats, what is the probability that there's only one student in the original position?


Inspiration

3 4 \frac 34 3 8 \frac 38 1 2 \frac 12 1 4 \frac 14

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1 solution

We can accomplish this by ignoring one of them as one person and seat are fixed.

Hence, we now we need to find Probabalility that none of the other 4 of them is alloted their correct positions. This is also called Derrangement.

The formula of Dearrangement is P ( n ) = 1 1 1 ! + 1 2 ! 1 3 ! + . . . . . . + ( 1 ) n 1 n ! P(n) = 1 - \dfrac {1}{1!} + \dfrac {1}{2!} - \dfrac {1}{3!} +......+ (-1)^n \dfrac {1}{n! }

where P ( n ) P(n) is probability that none of the n n number of people when arranged in a row sit in their original positions.

Put n = 4 , P ( 4 ) = 1 1 1 ! + 1 2 ! 1 3 ! + 1 4 ! = 12 4 + 1 24 = 9 24 = 3 8 n=4, \Rightarrow P(4) = 1 - \dfrac {1}{1!} + \dfrac {1}{2!} - \dfrac {1}{3!} + \dfrac {1}{4!} = \dfrac {12 -4 +1}{24} = \dfrac {9}{24} = \boxed {\dfrac 38}

Excellent explanation..!

Vijay Simha - 2 years, 5 months ago

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