5 students are arranged in a line.
If a teacher randomly reallocates their seats, what is the probability that there's only one student in the original position?
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We can accomplish this by ignoring one of them as one person and seat are fixed.
Hence, we now we need to find Probabalility that none of the other 4 of them is alloted their correct positions. This is also called Derrangement.
The formula of Dearrangement is P ( n ) = 1 − 1 ! 1 + 2 ! 1 − 3 ! 1 + . . . . . . + ( − 1 ) n n ! 1
where P ( n ) is probability that none of the n number of people when arranged in a row sit in their original positions.
Put n = 4 , ⇒ P ( 4 ) = 1 − 1 ! 1 + 2 ! 1 − 3 ! 1 + 4 ! 1 = 2 4 1 2 − 4 + 1 = 2 4 9 = 8 3