REALly Complex!

Level 2

x , y x, y and z z are real numbers satisfying 2 x 2 + y 2 + 2 z 2 − 8 x + 2 y − 2 x y + 2 x z − 16 z + 35 = 0. 2x^2 +y^2 + 2z^2 -8x+2y-2xy+2xz-16z+35=0. . Find the value of x − 5 y + 4 z x-5y+4z .


The answer is 33.

Shourya Pandey by Shourya Pandey , 22, India

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1 solution

Eshan Balachandar
May 12, 2016

( X − Y − 1 ) 2 (X-Y-1)^{2} + ( X + Z − 3 ) 2 (X+Z-3)^{2} + ( Z − 5 ) 2 (Z-5)^{2} =0

Z=5, X=-2, Y=-3

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