Rearrangement

Calculus Level 2

True or False ?

1 1 2 + 1 3 1 4 + 1 5 1 6 + 1 7 1 8 + 1 9 1 10 + 1 11 1 12 + = ( 1 1 2 1 4 ) + ( 1 3 1 6 1 8 ) + ( 1 5 1 10 1 12 ) + 1 - \frac 12 + \frac 13 - \frac 14 + \frac 15 - \frac 16 + \frac 17 - \frac 18 + \frac 19 - \frac 1{10} + \frac 1{11} - \frac 1{12} + \cdots \\ = \left(1 - \frac 12 - \frac 14\right) + \left(\frac 13 - \frac 16 - \frac 18\right) + \left(\frac 15 - \frac {1}{10} - \frac{1}{12}\right) + \cdots

False True

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2 solutions

Anthony Holm
Jun 22, 2017

The terms of an infinite series can only be rearranged, and still be considered equal, when the series is absolutely convergent. The alternating harmonic series is not absolutely convergent because the sum of the absolute value of its terms, the harmonic series, is well known to diverge. Thus if you change the order of the terms in the alternating harmonic series, the series can converge to a different value. (In fact it's possible to make it converge to any value you'd like.)

Why is it that the sum of an infinite series is the same no matter how you rearrange its terms, only if the series is absolutely convergent?

Zach Abueg - 3 years, 11 months ago
Arthur Conmy
Jun 26, 2017

This is an example of Riemann's Rearrangement Theorem

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