Reciprocal Recedes, Power Proceeds

Calculus Level 3

Suppose the maximum value of the function f ( x ) = ( 1 x ) x f(x)=\left(\dfrac{1}{x}\right)^x is M M . Evaluate ln ( ln ( M ) ) \ln(\ln(M)) .


The answer is -1.00.

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2 solutions

Sravanth C.
Dec 30, 2016

We first have to maximize the function, so we differentiate and equate the resulting expression to zero, because the function approaches a maximum or minimum value it's slope tends to zero. Differentiating the function twice we can get to know whether the function attains a maximum or minimum value.

f ( x ) = f ( x ) × ln ( 1 x 1 ) = 0 ln ( 1 x ) = 1 x = 1 e \begin{aligned} f'(x) = f(x) \times \ln\left(\frac 1x - 1\right)&=0\\ \ln\left(\frac 1x \right)&=1\\ x&=\frac 1e\\ \end{aligned}

Hence the function attains a maximum value at this point. Therefore ln ( ln ( e 1 / e ) ) = 1 \ln(\ln(e^{1/e} ))=-1 .

You have found the critical point correctly, but you haven't computed the maximum value. Also you need to show that the second derivative is indeed less than 0 for the critical point.

Nihar Mahajan - 4 years, 5 months ago

x x = 1 e \cfrac {1}{e}

why? \quad \quad \quad

Pi Han Goh - 4 years, 5 months ago

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