Recollect the past 1!

Classical Mechanics Level 4

A Projectile is projected with speed u at an angle of 60 degree with the horizontal from the foot of an inclined plane.

If the projectile hits the inclined plane horizontally , Find the range of projectile measured along the incline.

Details and assumptions

The projectile does not move anywhere after hitting the inclined ONCE.

u = 10 m/sec

g= 10 m/sec^2

Give your answer in metres to 3 significant figures.

Angle of inclination of inclined with horizontal is less than 60 degrees

Neglect Any kind of disspative force

For the problem writing party

The answer is 5.73.

1 solution

Shivam Mishra
Apr 1, 2016

Since the projectile hits the inclined plane horizontally,it is easy to understand that it is at its maximum height(since velocity vector of a projectile is parallel to the ground at its highest point).

Maximum height attained by the projectile $H=(u^2sin^2A)/2g$ where $A$ is the angle of projection. Evaluating this we get that the height attained by the projectile is $3u^2/8g$ . Now evaluating the horizontal range for this vertical motion we get that $r=\sqrt{3}u^2/4g$

Range along inclined plane is equal to $R=\sqrt{H^2+r^2}=(\sqrt{21}u^2)/8g$

Substituting value of $g$ and evaluating further we get:

$\boxed{R=5.728}$

Recollect the past 1!

The answer is 5.73.

1 solution

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