Recollect the past 7!

A Particle is projected from O O on the ground with velocity u u at an angle x x with the horizontal. It strikes at a point C C on a fixed smooth plane A B AB having inclination theta with the horizontal as shown in the figure below. If the particle does not rebound from the plane, then find maximum height from the ground to which the particle rises.

Details And Assumptions :

The particle does not get stuck to the plane at point of striking(Point C in the figure) that is it can move further on the plane. The collision is perfectly inelastic and particle can move along the plane

All the given Below details are in SI Units

tan ( x ) = 0.5 \tan(x) = 0.5 , sin ( θ ) = 0.6 \sin(\theta) = 0.6 , g = 10 g = 10 , u = 5 5 u = 5\sqrt5 .

OA = 10/3 m


For the problem writing party.


The answer is 4.45.

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1 solution

Aniket Sanghi
Apr 6, 2016

Quite tricky , but easy

First solve initial steps, you would get to know that the ball strikes the incline when it is at its highest point of its journey .

After striking we have to equate the component of velocity in the direction normal to incline to zero (as mentioned in question)...consider the component of velocity along the incline ....then find the max height attained from this position and add it to the height of point of strike, this will give you the highest point attained.

Which comes out to be 1.25 + 3.2 = 4.45 1.25 + 3.2 = \boxed{4.45}

Prakhar! I was working on with combinatorics for some time.....you would like to solve my sets ......you can get them from my posts .....

Aniket Sanghi - 5 years, 2 months ago

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ok will surely try them

Prakhar Bindal - 5 years, 2 months ago

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You can improve the grammar of ques by mentioning inelastic collision

Aniket Sanghi - 5 years, 2 months ago

Hence The particle should strike the plane perpendicularly and can move along the plane---what does this mean?,then.

Ashish R Nair - 5 years, 2 months ago

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It won't strike perpendicularly .......I told it will strike in direction parallel to ground

Aniket Sanghi - 5 years, 2 months ago

Inelastic collision

Aniket Sanghi - 5 years, 2 months ago

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Exactly! :)

Prakhar Bindal - 5 years, 2 months ago

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