is a rectangle whose vertices lie on the circumference of the ellipse .
Let is the maximum area of and is the area of the ellipse. Then the value of can be written as . Find .
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take a point on the ellipse as P. P=acosx,bsinx. now the rectangle is symmetrical about the diagonal. so the opp. vertex will be -acosx,-bsinx as it will be in the 3rd quad. further take the diagonal of the rec in terms of a and b you will see that length of the rec. will come 2acosx and breath will be 2bsinx area=4absinxcosx =2absin2x max. area =2ab (sin2x has max value =1) 2ab/pie a b(pie a b = area of the ellipse. so the ans is 2.