Find the area of the greatest rectangle that can be inscribed in in the ellipse .
Take .
For more problems try my set
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Let me recycle an idea I have used before, showing that we don't even need calculus.
We can parameterize the ellipse as x = a cos ( t ) and y = b sin ( t ) so that the area of an inscribed rectangle is A = 4 x y = 4 a b cos t sin t = 2 a b sin ( 2 t ) for 0 < t < 2 π . The maximum of 2 a b is attained when t = 4 π .