Rectangles Are Cool!

Geometry Level 5

In the figure above, A B C D ABCD is a rectangle, P B = 10 cm PB= 10 \text{ cm} , A S = 8 cm AS = 8 \text{ cm} , Q C = 12 cm , D R = 8 cm QC=12 \text{ cm}, DR=8 \text{ cm} . The area of the triangle P O Q POQ and triangle O S R OSR are both 30 cm 2 30\text{ cm}^2 . And O O is the intersection point of the straight lines P R PR and Q S QS . Find the area of the rectangle A B C D ABCD (in m 2 \text{m}^2 ).


Credits to my math teacher for coming up with this problem.


The answer is 0.0238.

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5 solutions

Neel Maiti
Nov 28, 2015

The solution is too long for me to write so I have uploaded the pics which show the solution of this problem,I would like someone else to come up with a more simpler and elegant way of the solution to this question. Please be free to ask if you don't understand any part of my approach!



I missed it in cm and m!!

Niranjan Khanderia - 3 years, 9 months ago
Michael Mendrin
Nov 28, 2015

Why on earth would all the dimensions be given in c m cm , and then the answer in m 2 {m}^{2} be asked for??

To trick the solver :)

pickle lamborghini - 5 years, 6 months ago

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It worked on me.

Michael Mendrin - 5 years, 6 months ago

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Yes to start with I knew it was in meter. But while giving answer I too forgot !!

Niranjan Khanderia - 3 years, 9 months ago
Anthony Hong
Dec 9, 2015

@eugene, your math teacher didn't say the answer is in m square...

Lu Chee Ket
Nov 29, 2015

O (6.8, 8.4) with h = 5 and k = 4 added as (10 + 4)(5 + 12) = 238 c m 2 cm^2

0.14 × 0.17 = 0.0238 0.14 \times 0.17 = 0.0238 ( m 2 ) (m^2)

Answer: 0.0238 \boxed{0.0238}

How did u get the coordinates of point O?

neel Maiti - 5 years, 6 months ago

It is sufficient to know that the area of the triangles are equal, I didn't use the number 30:

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