In the figure above,
A
B
C
D
is a rectangle,
P
B
=
1
0
cm
,
A
S
=
8
cm
,
Q
C
=
1
2
cm
,
D
R
=
8
cm
. The area of the triangle
P
O
Q
and triangle
O
S
R
are both
3
0
cm
2
. And
O
is the intersection point of the straight lines
P
R
and
Q
S
. Find the area of the rectangle
A
B
C
D
(in
m
2
).
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Why on earth would all the dimensions be given in c m , and then the answer in m 2 be asked for??
To trick the solver :)
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It worked on me.
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Yes to start with I knew it was in meter. But while giving answer I too forgot !!
@eugene, your math teacher didn't say the answer is in m square...
O (6.8, 8.4) with h = 5 and k = 4 added as (10 + 4)(5 + 12) = 238 c m 2
0 . 1 4 × 0 . 1 7 = 0 . 0 2 3 8 ( m 2 )
Answer: 0 . 0 2 3 8
How did u get the coordinates of point O?
It is sufficient to know that the area of the triangles are equal, I didn't use the number 30:
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The solution is too long for me to write so I have uploaded the pics which show the solution of this problem,I would like someone else to come up with a more simpler and elegant way of the solution to this question. Please be free to ask if you don't understand any part of my approach!