Find the number of rectangles that can be obtained by joining 4 of the 12 vertices of a 12-sided regular polygon.
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I think that it's more accurate to say that you can choose 2 points from one-half of the circle (6 points) and ensure that for each picking of 2 points, you can make a mirror image on the other half of the circle to make a rectangle. Thus, there are 6C2 = 15 different rectangles. (Of course, I could be misinterpreting your words and that this is what you meant to say originally.)
Upvoted for a more creative solution than casework.
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This is a way better solution than casework. But I wonder why my casework strategy didn't work. I got an answer of 18 (6 of every kind) and it's obviously wrong. So what's the issue?
Can you please add some figure to give better explanation.
Why only rectangle why not any quadrilateral
6C4 will also contain quadrilateral which are not rectangles
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No you are absolutely wrong there.You are lacking basic concepts.
The diagonals of the rectangle must pass through center of the polygon (circle , since the polygon is definitely cyclic) , we have 6 pairs of points forming diameter , selecting any two out of them will ensure the formation of a rectangle with them as diameter, therefore our answer is ( 2 6 ) = 1 5
Note that any diagonal that is not a diameter corresponds to 1 rectangle. However, for each rectangle, there are 4 diagonals; thus, the number of rectangles is the number of non-diameter diagonals divided by 4.
Each of the 12 points connects to 10 non-diameter diagonals. However, each diagonal connects to 2 points; thus, the number of non-diameter diagonals is 12*10/2=60
Thus, the number of rectangles must be 60/4=15.
The number of diagonals of the polygon passing though its center =6 and hence number of rectangles =6C2=15
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In very simple words:
If we divide 12 points of the 12 sided regular polygon into two parts, each will contain 6 points, and we know that a rectangle can be formed by 4 points, which can be selected in 6C4 ways. Thus 15 is the answer.