A regular five pointed star is inscribed in a circle of radius 10 as shown. Find the area of the yellow region to the nearest integer.
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Apply sine law on the figure on the right.
sin 3 6 x = sin 1 2 6 1 0 ⟹ x = 1 0 ( sin 1 2 6 sin 3 6 ) ≈ 7 . 2 6 5
The area of the star is equal to the area of this triangle multiplied by 10 (since there are 10 triangles). So the area of the star is 2 1 ( 1 0 ) ( 7 . 2 6 5 ) ( sin 1 8 ) ( 1 0 ) ≈ 1 1 2 . 2 5 .
The area of the yellow region is equal to the area of the circle minus the area of the star. We have
A = π ( 1 0 ) 2 − 1 1 2 . 2 5 ≈ 2 0 2