Red five-pointed star

Geometry Level pending

A regular five pointed star is inscribed in a circle of radius 10 as shown. Find the area of the yellow region to the nearest integer.

183 307 216 202

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1 solution

Apply sine law on the figure on the right.

x sin 36 = 10 sin 126 \dfrac{x}{\sin 36}=\dfrac{10}{\sin 126} \implies x = 10 ( sin 36 sin 126 ) 7.265 x=10\left(\dfrac{\sin 36}{\sin 126}\right) \approx 7.265

The area of the star is equal to the area of this triangle multiplied by 10 (since there are 10 triangles). So the area of the star is 1 2 ( 10 ) ( 7.265 ) ( sin 18 ) ( 10 ) 112.25 \dfrac{1}{2}(10)(7.265)(\sin 18)(10) \approx 112.25 .

The area of the yellow region is equal to the area of the circle minus the area of the star. We have

A = π ( 10 ) 2 112.25 202 A=\pi (10)^2 - 112.25 \approx \color{#69047E}\boxed{202}

The problem says that the circle has a radius of 5 not 10.

Victor Paes Plinio - 3 years, 4 months ago

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