If an
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×
n
grid composed of unit squares has a red perimeter, and exactly 44 of the unit squares have exactly one red side, how long are the sides of the
n
×
n
square?
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according to me... it can be solved by a simple logic dear , actually.. the total number of small squares having one side red is 44. and all the sides would have same number of these type of squares.. soo one side will have 44/4=11 small squares with one red side...Now the first and the last square of each side has two red sides.. therefore thy are not included in this count,i.e, 11... and soo we can say.. that total no. of squares in one side = 11+2=13 .... as it is stated that each side has a unit length... soo, length of the n*n square = 13 units. :D
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But adding this way counts the corner squares twice.
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Dude.. when we're talking of squares having one side red then we are not counting the corner squares. We are adding the corner squares at last just to get the length of the side.
didn't get the question~lol~
Sorry I didn't know what you want to do?
44/4=11 and then give 4 edge blocks we get 13 blocks per side
With the answer n x n, where n=13 then if someone is given 13x13 and asked to create a pictoral version, they would not create the correct pictoral of n x n. This scenario is meant to fool for a false answer. In my opinion the proper question should have been to solve for the perimeter given that it is a level one question.
ya i got the answer 12 how it is 13. i couldn't understand. please give the way
Same here .
I agree. @Arron Kau , please change the wording of this question.
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You are correct. I've fixed it to say "exactly one side" as that was the intent of the question. It got messed up during a previous edit. My apologies.
I agree man the question is not correct
sorry i didnt get the question.. @Arron Kau
But doesn't the question say "exactly one side"? Maybe it has been updated since this solution was posted.
How long are the sides of square=how long is the perimeter of the square, I though that
Number of Squares with exactly 1 red side is 44. Read the question carefully.
Just equate 44 to the formula in the previous question, which is 4 ( n − 2 ) . This gives us 4 ( n − 2 ) = 4 4 n − 2 = 1 1 n = 1 3
Good and simple logic,thanks! K.K.GARG,India
i can not understand this formula 4(n-2)=44... plzzzz tell me about this @ [email protected]
44 SIDES HAVE ONE RED SIDE.IT IS A SQUARE SO FOUE SQUARE MUST HAVE TWO RED SIDE AT THE EDGE.ON SKETCHING THE DIAGRAM WE CAN FIND THAT ONE SIDE OF THE SQUARE MEASURE ABOUT 13 UNITS.. SIMPLE .... CONGRATZ FOR THOSE WHO TRIED IT ....
No. of squares with exactly one red side = 44. The corner squares will have two red sides. No. of small squares with exactly one red side on any given side of the bigger square = 44/4= 11. Adding the two corner squares, 11 + 2 =13. Hence, length of the square is 13 units.
total no of square on the perimeter excluding the corner are 44 that's 11 on all sides adding the 2 corner pieces we get 13
the question is correct..remove one unit square from each corner f the big square because they have two sides red.hence u get 14 unit squares at each side..14 *4=56 single red colour squares..but we want total 44 single red colour unit squares,so divide 44/4=11..now.11 is single red unit squre..to get full length add 2,11+2=13..so,13 is ur answer
No.... C... U have to do the calculations individually....
44÷4=11. 11 is the no. Of squares with only one side red...
Then add 2(non red sides)
Hence... 13
The correct formula is : (n - 2) x 4, we saw it in the previous item. So, let´s apply the formula on reverse : 44/4 + 2 = 13 The square is 13 x 13
Interesting but the ans is 13.
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2nd problem is to find the no of unit squares painted red on only one side for that we identified the formula as 4 (n-2) but in this question it says atleast one red side then answer should be 12 right ?
Plz explain.
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@chandrachur - 2nd problem is to find the no of unit squares painted red on only one side so for that we identified the formula as 4 (n-2) but in this question it says atleast one red side then answer should be 12 right ?
He did 44/4, but forgot the +2
Thank you Zaid
on May 11 Jagadeshwar K wrote 'it says at least one red side then answer should be 12 right ?' ...... ....... No - it would be 11, because it was still 44 small squares with at least one red side, which would include the corner small squares; and each corner small square belongs to 2 sides of the large square, so 44/4 = 11
Each corner unit square has 2 sides which are included in the red outline. Each side of the big square has 2 corner squares. Since the 44 unit squares mentioned in the question have only 1 red side, they do not include the corner unit squares. Each side has n-2 (excluding the two corner unit squares) unit squares which are part of the 44 unit squares, therefore (n-2)x4 = 44. Solving this, n-2= 44/4, then n-2 = 11, n = 11+2 and finally n=13.
got it @Swati Singh Paraste
The only pieces with 1 red side are the non-corner edge pieces. We have 44 of those and are given the fact that our figure is a square. This means there is an equal number of 1-red-sided pieces on each side of the figure, and 44/4 =11. There are 11 non-corner edge pieces per edge, and each edge has two corners, giving us 13 total pieces per edge.
Just remember the square in the corner of the bigger square has 2 side colored red
From the previous problem we get: 4(n-2)=44
n-2=11
hence n=13
Its simple there r 4sides and 4cubes should not be taken at 4 vertices and as there r 4sides each side have 44/4 cubes and 2cubes should be taken in to account which r at corners of side of square. So 11 plus 2 gives 13
From the previous problem: 4(n-2)=44 n-2=11 n=13
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With the limitations of my thinking skills i happen to find a flaw in the question. It says : NUMBER OF SQUARES WITH - AT LEAST 1 RED SIDE - IS 44.Now that seems to include squares with red sides >=1 i.e with 2 red sides also. So the ans should be 4(n-1)=44 or, n=12. Plz inform if i went wrong.