Redical expression

Algebra Level 2

1/3√32+1/2√8-1/5√50

4/3√2 4/3√3 1/3√3 1/3√2

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2 solutions

Aryan Gaikwad
Feb 27, 2015

= 32 3 + 8 2 50 5 = 2 4 2 3 + 2 2 2 2 5 2 2 5 = 4 2 3 + 2 2 2 5 2 5 = 4 2 3 + 2 2 2 2 = 4 2 3 =\frac { \sqrt [ ]{ 32 } }{ 3 } +\frac { \sqrt [ ]{ 8 } }{ 2 } -\frac { \sqrt [ ]{ 50 } }{ 5 } \\ =\frac { \sqrt [ ]{ { 2 }^{ 4 }\cdot 2 } }{ 3 } +\frac { \sqrt [ ]{ { 2 }^{ 2 }\cdot 2 } }{ 2 } -\frac { \sqrt [ ]{ { 5 }^{ 2 }\cdot 2 } }{ 5 } \\ =\frac { 4\sqrt [ ]{ 2 } }{ 3 } +\frac { 2\sqrt [ ]{ 2 } }{ 2 } -\frac { 5\sqrt [ ]{ 2 } }{ 5 } \\ =\frac { 4\sqrt [ ]{ 2 } }{ 3 } +\sqrt [ 2 ]{ 2 } -\sqrt [ 2 ]{ 2 } \\ =\frac { 4\sqrt [ ]{ 2 } }{ 3 }

Both answer and question are confusing.

Muthukumar Subramanian S - 6 years, 3 months ago

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Where exactly are you confused in the answer?

Aryan Gaikwad - 6 years, 3 months ago

Even I felt the same.

Rama Devi - 6 years, 1 month ago

There would be no ambiguity if the problem is put as 32 3 + 8 2 50 5 \dfrac{\sqrt{32} }{3}+\dfrac{\sqrt{8} } {2}-\dfrac{\sqrt{50} } {5} = 4 2 3 + 2 2 2 5 2 5 = 2 { 4 3 + 1 1 } = 4 2 3 =4*\dfrac{\sqrt2 }{3}+2*\dfrac{\sqrt{2} }{2}-5*\dfrac{\sqrt{2} }{5}\\=\sqrt2* \{\dfrac{4}{3 } +1-1\} \\= 4*\dfrac{\sqrt2 }{3}

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