Redox reaction

Chemistry Level 1

Redox (reduction-oxidation) reactions include all chemical reactions in which atoms have their oxidation state changed; in general, redox reactions involve the transfer of electrons between species. The above left figure shows potassium dichromate and the above right one depicts chromium (III) oxide. The reaction formula for creating chromium (III) oxide from potassium dichromate is as follows: 2K 2 Cr 2 O 7 ( a q ) + 2 H 2 O ( l ) + 3S ( s ) 4KOH ( a q ) + 2Cr 2 O 3 ( s ) + 3SO 2 ( g ) . \begin{aligned} \text{2K}_2\text{Cr}_2\text{O}_7(aq) &+2\text{H}_2\text{O}(l)+\text{3S}(s) \\ &\to \text{4KOH}(aq)+\text{2Cr}_2\text{O}_3(s)+\text{3SO}_2(g). \end{aligned} What are the oxidizing agent and the reducing agent?

Oxidant - S, Reductant - Kr 2 _2 Cr 2 _2 O 7 _7 Oxidant - H 2 _2 O, Reductant - S Oxidant - Kr 2 _2 Cr 2 _2 O 7 _7 , Reductant - S Oxidant - Kr 2 _2 Cr 2 _2 O 7 _7 , Reductant - H 2 _2 O

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2 solutions

Kenny Lau
Jul 9, 2014

Oxidant causes oxidation, reductant causes reduction (yds)

Lu Chee Ket
Jan 29, 2016

K 2 C r 2 O 7 K_2 Cr_2 O_7 oxidized S S into S 4 + S~^{4+} ;

S S reduced C r 6 + Cr~^{6+} into C r 3 + Cr~^{3+} ;

H + H~^+ + O H OH~^- + O 2 O~^{2-} \rightarrow 2 O H 2~ OH~^- tells that water is also a reductant effectively, but it only take away extra O 2 O~^{2-} while not helping K + K~^+ or C r 6 + Cr~^{6+} to reduce oxidation states directly.

Therefore, K 2 C r 2 O 7 K_2 Cr_2 O_7 is oxidant while S S is reductant; Here, K 2 C r 2 O 7 K_2 Cr_2 O_7 cannot have O O~^- but O 2 O~^{2-} as 7 is odd while both K K and C r Cr are even. Consequently, we can only deduce for C r 6 + Cr~^{6+} as oxidation state.

Answer: O x i d a n t K 2 C r 2 O 7 , R e d u c t a n t S \boxed{Oxidant - K_2 Cr_2 O_7, Reductant - S}

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