P
=
(
p
x
,
p
y
)
is a point in the plane.
X
is the reflection of
P
across the
x
-axis.
Y
is the reflection of
P
across the
y
-axis.
What point must the line X Y pass through?
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Without having to work out the equation of the line, we can say that the gradient of − P x P y means that for every P x across, the line moves P y down. Since it starts at Y = ( − P x , P y ) , moving P x across and P y down brings it to the origin.
S , half way between points Q and R , has coordinates which are the average of the coordinates of those two points. S = ( 2 P x − P x , 2 − P y + P y ) = ( 0 , 0 )
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X = ( p x , − p y ) and Y = ( − p x , p y )
The slope of the line is p x − ( − p x ) − p y − p y = − p x p y .
From the slope, we get that the equation of the line is y = − p x p y x .
Thus, this line passes through the origin ( 0 , 0 ) .