Reflecting Points

Geometry Level 3

P = ( p x , p y ) P = (p_x,p_y) is a point in the plane.
X X is the reflection of P P across the x x -axis.
Y Y is the reflection of P P across the y y -axis.

What point must the line X Y XY pass through?

( 1 , 1 ) (1,1) O = ( 0 , 0 ) O = (0,0) P = ( p x , p y ) -P = (-p_x, -p_y ) P P

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2 solutions

Chung Kevin
Nov 16, 2016

X = ( p x , p y ) X = ( p_x, - p_y ) and Y = ( p x , p y ) Y = (- p_x, p_y )

The slope of the line is p y p y p x ( p x ) = p y p x \frac{ -p_y - p_y } { p_x - (-p_x) } = - \frac{p_y} { p_x} .
From the slope, we get that the equation of the line is y = p y p x x y = - \frac{p_y}{p_x} x .

Thus, this line passes through the origin ( 0 , 0 ) (0,0) .

Ah! So this is what you are trying to say! :)

Michael Huang - 4 years, 7 months ago

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Is the question clear? Not many people answered this question.

Chung Kevin - 4 years, 7 months ago

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Yep! Thanks for the clarification!

Michael Huang - 4 years, 7 months ago

Without having to work out the equation of the line, we can say that the gradient of P y P x -\frac{P_y}{P_x} means that for every P x P_x across, the line moves P y P_y down. Since it starts at Y = ( P x , P y ) Y=(-P_x,P_y) , moving P x P_x across and P y P_y down brings it to the origin.

Dan Ley - 4 years, 6 months ago
Marta Reece
Mar 9, 2017

Point S S , half way between points Q Q and R R , has coordinates which are the average of the coordinates of those two points. S = ( P x P x 2 , P y + P y 2 ) = ( 0 , 0 ) S=(\frac{P_x-P_x }{2},\frac{-P_y+P_y }{2})=(0,0)

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