Regents Question

Two cars, A and B, are 400 meters apart. Car A travels due east at 30 meters per second on a collision course with car B, which travels due west at 20 meters per second. How much time elapses before the two cars collide, in seconds?


The answer is 8.

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2 solutions

Azadali Jivani
Jan 28, 2015

In 1 sec. both the cars cover a distance of 50 meters (30+20). So 1 meter in ....1/50sec Therefore 400 meter in ........1/50*400 = 8 sec (Ans.)

I made a system of equations because everything I do is overcomplicated

Hobart Pao - 6 years, 4 months ago
Caleb Townsend
Feb 18, 2015

One car's speed relative to the other's is ( 30 + 20 ) m s = 50 m s . (30 + 20)\frac{m}{s} = 50\frac{m}{s}.
The distance between them is 400 m . 400 m.
Therefore the time to collision is 400 m 50 m / s = 8 s \frac{400 m}{50 m/s} = \boxed{8 s} Note that if the information the asker gave us is correct, they will collide in 8 8 seconds; in real life, hopefully someone moves out of the other's way.

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