Regular Polygons and their Interior Angles

Geometry Level pending

A regular polygon with n n sides has an interior angle of x x^\circ . Which of the following is equal to the interior angle of a regular polygon with 2 n 2n sides?

180 + x 180 + x 60 + x 60 + x 90 + x 90 + x 90 + 0.5 x 90 + 0.5x 180 + 0.5 x 180 + 0.5x

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2 solutions

Marta Reece
May 5, 2017

Internal angle of a regular polygon with n n sides is x = 18 0 36 0 n x=180^\circ-\frac{360^\circ}{n}

Therefore n = 36 0 18 0 x n=\frac{360^\circ}{180^\circ-x}

Substituting this into expression for the internal angle of a polygon with 2 n 2n sides: 18 0 36 0 2 n = 9 0 + x 2 180^\circ-\frac{360^\circ}{2n}=\boxed{90^\circ+\frac{x}{2}}

Internal angle of an n n -sided regular polygon is given by

θ ( n ) = 180 ( n 2 ) n = 180 360 n = x θ ( 2 n ) = 180 360 2 n = 90 + 1 2 ( 180 360 n ) Note that 180 360 n = x = 90 + x \begin{aligned} \theta(n) & = \frac {180(n-2)}n = \color{#3D99F6} 180 - \frac {360}n = x \\ \theta (2n) & = 180 - \frac {360}{2n} \\ & = 90 + \frac 12 \left({\color{#3D99F6} 180 - \frac {360}n} \right) & \small \color{#3D99F6} \text{Note that } 180 - \frac {360}n = x \\ & = \boxed{90 + \color{#3D99F6} x} \end{aligned}

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