Regulars...

Geometry Level 1

$\Delta$ $ABM$ is Equilateral Triangle and $ABCD$ is Square, then find $\angle DMC$ (in degrees).

2 solutions

Roger Erisman
Dec 15, 2018

MAB = 60 = MBA. Eq triangle

DAM = CBM = 30. Rt angle - 60

BCM = ADM = 75. Base angle of isosceles triangle( 180 - 30)/2

CDM = DCM = 15. Rt angle - 75

DMC = 150. 180 - 2*15

X X
Aug 1, 2018

$\angle MAB=60^\circ,\angle DMA=30^\circ,\angle AMD=\frac{180^\circ-30^\circ}{2}=75^\circ,\angle DMC=360^\circ-75^\circ-60^\circ-75^\circ=150^\circ$