Relative time

A spacecraft is moving relative to the earth. During a certain time period, an observer on the earth finds that 3601 3601 seconds have elapsed according to her clock, while the clock on the spacecraft changed from 1 pm to 2 pm . What is the spacecraft's approximate speed relative to the earth?

3.6 × 1 0 5 m/s 3.6 \times 10^{5} \text{ m/s} 3.6 × 1 0 6 m/s 3.6 \times 10^{6} \text{ m/s} 7.1 × 1 0 6 m/s 7.1 \times 10^{6} \text{ m/s} 7.1 × 1 0 5 m/s 7.1 \times 10^{5} \text{ m/s}

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1 solution

Siva Prasad
May 16, 2015

lorentz factor = 3601/3600 =1.000277778

(v/c)^2 = 5.5e-4

v =7069595 m/s

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