Relativity and time [2]

Classical Mechanics Level pending

Consider a clock that is in flat space-time, far away from any masses. If 100 100 seconds passes on this clock, what time passes on a clock near the surface of a white dwarf star with a mass 1.8 × 1 0 30 k g 1.8 \times 10^{30} kg and radius 6.1 × 1 0 6 m 6.1\times 10^{6} m

Newtonian Gravitational constant, G N = 6.67408 × 1 0 11 G_{N} =6.67408\times10^{-11}

Speed of light , c = 2.99792 × 1 0 8 c=2.99792\times10^{8}

All constants are in SI units.

Time Dilation


The answer is 99.978.

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1 solution

Amal Hari
Feb 25, 2019

Δ t 0 Δ t = 1 2 G N M R 0 c 2 \dfrac{\Delta t_{0}}{\Delta t_{\infty}}=\sqrt{1-\dfrac{2G_{N}M}{R_{0}c^{2}}}

R 0 = 6.1 × 1 0 6 R_{0}=6.1\times 10^{6}

M = 1.8 × 1 0 30 M=1.8\times 10^{30}

Δ t = 100 \Delta t_{\infty}=100

Substituting and solving will give 99.978 99.978

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