Remainder!

If A and B are positive integers such that the reminder is 4 when A is divided by B, What is the smallest possible value of A+B?

5 4 13 9

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

DarkMind S.
Apr 1, 2017

The Reminder always has to be less than the divisor. Otherwise, the quantity equal to the divisor can be subtracted from the remainder and written as a factor of the divisor. Which mean the remainder would have a different value after all. The smallest number greater than 4 is 5. So A is 5. Now, what is the smallest number that we should divide by 5 that gives us a reminder of 4 ? Well, 4. So B = 4. 5+4 = 9

Now, go ahead and mark this as the best answer please, because you're not going to get a better one

Mamun Abdullah
Sep 12, 2015

Since A/B has a remainder of 4, so B must be at least 5. Next Possible value of A can be 4,9,14,19… But the smallest value of A is 4. So A+B is 9.

Can you please elaborate your method a little more ?

Thank you

Syed Baqir - 5 years, 9 months ago

4/5 does not have a remainder of 4 and neither does 5/4.

Curt Ginter - 4 years, 9 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...