Remainder-2

$\begin{aligned} 2^{\lambda(7)}\equiv 2^6\equiv 1&\pmod {7}\\ \implies\boxed{ 87\pmod{7}}\\ 87\equiv 7\times 12+3\equiv 3&\pmod{7}\\ \implies 2^{87}\equiv 2^3\equiv 1&\pmod{7}\\ \implies 2^{87}+3\equiv \boxed{4}&\pmod{7} \end{aligned}$