There are two nunbers a and b both are divided by another number 10 and we get remainder *1 and 9 respectively . Now what will be the remainder of 1 0 a b
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a = 1 0 k 1 + 1 for some k 1 .
b = 1 0 k 2 + 9 for some k 2 .
1 0 a b = 1 0 ( 1 0 k 1 + 1 ) ( 1 0 k 2 + 9 )
1 0 a b = 1 0 1 0 0 k 1 k 2 + 9 0 k 1 + 1 0 k 2 + 9
1 0 a b = 1 0 k 1 k 2 + 9 k 1 + k 2 + 1 0 9 so the remainder is 9 .
(Or, if you know modular arithmetic, you get that result much faster.)
BTW i knew that the remainder of ab/10 and r1 r2/10 will be same so i just did 1 9/10
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a=1mod10... (1)
b=9mod10... (2)
multiplying (1) and (2) together gives
ab = 9mod10
So remainder of ab/10 is 9.