Remaining remainder!

Find the remainder when 1 ! + 2 ! + 3 ! + 4 ! + 5 ! + + 47 ! 1!+2!+3!+4!+5!+\ldots+47! is divided by 20.

19 12 15 17 10 13

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1 solution

Dylan Pentland
Jun 5, 2015

Starting with 5 ! 5! if we expand the factorials at some point we find . . . 4 × 5... ...4\times5... meaning all of those are 0 0 in modulo 20 20 . Now just find the first 4 terms mod 20: 1 ! + 2 ! + 3 ! + 4 ! = 33 13 ( m o d 20 ) 1!+2!+3!+4!=33\equiv13 \pmod{20}

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