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Isn't it also defined for 0 i.e for all non negative integers since adding 2 zero times simply implies no addition at all i.e 0 which us equal to 2 ( 0 ) = 0 .
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Ah, you're right! I made a mistake. Lemme change it now. Thanks!
Actually the LHS is incorrect. x times mean x is whole number. So this is true for whole numbers only. Other method, differentiate both the sides wrt x, you will get 0+0+0+0...+0=2. This is obviously not true. This happens because equation defined for set of whole numbers is not differentiable.
Your solution is incomplete. It is only defined for non-negative whole numbers. You don't add a number − 5 times
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Integers are negative, not whole numbers
I mentioned whole numbers
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Oh...ah ah. Whole numbers! My bad, I made a mistake. Sorry
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Note that x times 2 + 2 + 2 + … + 2 is only defined for non-negative integers x . Negative numbers, decimals, fractions and irrational numbers all will cause this expression to be undefined.
You simply cannot write 2 + 2 + 2 + … + 2 for 1 0 . 5 times, − 1 0 times, 7 4 3 times or π times. It's simply not possible.
If you still do not get it, consider this:
If x = 1 0 . 5 , 2 x = 2 1
2 + 2 + 2 + … + 2 = 2 1 is simply not possible, no matter how many or how few 2 's you write.
Therefore,
x times 2 + 2 + 2 + … + 2 = 2 x
for all non-negative integers x . The answer is False