Replace the "?"

$19\times {0}=0$

$19\times{1}=19$

$19\times{2}=38$

$19\times {3}=57$

$19\times {4}= \boxed {76}=?$

$19\times {5}=95$

Left digits 1,3,5, precedin is 7. Right digits 9,8,7, preceding term vil b 6, so 76 n as same d next term is 9 and 5, 95.

I did 1+9 = 10, then it jumps 2 numbers on the first digit, and 3+8=11, jump 2, 5+7=12, jump 2, 7+?=13. 7+6=13

Un = a + (n - 1) X d = 0 + (5 - 1) X 19 = 76

19+19+19...

multiples of 19 simple!!

just add 19

because 19*4=76

It is the table of 19..

0+19=19, 19+19=38, 38+19=57, 57+19=76, 76+19=95 ,

19 0=0 19 1=19 19 2=38 19 3=57 19 4=76 19 5=95

leave the 0,10x2-1,20x-2,30x3-3,40x2-4,50x2-5

19 plus 57 = a 76

solving problem in complicated way is not solution

19-38 is 19,38-57 is 19 it's a pattern

I didn't even realise was the 19x Table.

I did 3 x 6 + 1 then 6 x 6 + 2 then 9 x 6 + 3 then 12 x 6 plus 4 and 15 x 6 plus 5. Insane