The Parallel Resistance

Find the equivalent resistance of the infinite network where each resistance is of 1 Ω 1\Omega .

Give your answer up to 4 decimal places.


The answer is 2.73205.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The resistance of each resistor connected in the circuit is of 1Ω.

The equivalent resistance of the circuit = R R'

R = 1 + R R + 1 + 1 \large \therefore R' = 1 + \frac{R'}{R' + 1} + 1

R 2 2 R 2 = 0 \large \implies R'^2 - 2R' - 2 = 0

R = 2 ± 4 + 8 2 \large \implies R' = \frac{2 \pm \sqrt{4 + 8}}{2}

R = 2 ± 12 2 \large \implies R' = \frac{2 \pm \sqrt{12}}{2}

R = 1 ± 3 \large \implies R' = 1 \pm \sqrt{3}

The negative value of resistance cannot be accepted. Hence R = 1 + 3 \large R' = 1 + \sqrt{3}

R = 1 + 3 \large \therefore R' = 1 + \sqrt{3}

R = 1 + 1.73205 \large R' = 1 + 1.73205 = 2.73205 Ω \large 2.73205\Omega

\therefore The Equivalent resistance of the infinite network is 2.73205 Ω \boxed {2.73205\Omega}

Best explanation I have come across. Thanks for taking the time! Cheers :)

B.S.Bharath Sai Guhan - 5 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...